Question 9 Answer:
If not, then examine these calculations to see how you went amiss.
We are given the molarity of a base, and we know that the molarity of an acid is equal to the OH- ions. OH- = 1.86e-12 pOH = -Log (OH-) pOH = -Log (1.86e-12) pOH = 11.73 pH = 14 - pOH pH = 14 - 11.73 pH = 2.27 H+ = 2nd Log (-pH) H+ = 2nd Log (-2.27) H+ = 5.37e-3 |