Question 5 Answer:
If not, then examine these calculations to see how you went amiss.
OH- = 3.8e-11 pOH = -Log (OH-) pOH = -Log (3.8e-11) pOH = 10.42 pH = 14 - pOH pH = 14 - 10.42 pH = 3.58 H+ = 2nd Log (-pH) H+ = 2nd Log (-3.58) H+ = 2.63e-4 |