Question 2 Answer:
If not, then examine these calculations to see how you went amiss.
H+ = 7.76e-3 pH = -Log (H+) pH = -Log (7.76e-3) pH = 2.11 pOH = 14 - pH pOH = 14 - 2.11 pOH = 11.89 OH- = 2nd Log (-pOH) OH- = 2nd Log (-11.89) OH- = 1.28e-12 |